(2x-5)(2x^2+10x+25)=0

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Solution for (2x-5)(2x^2+10x+25)=0 equation: 


Simplifying
(2x + -5)(2x2 + 10x + 25) = 0

Reorder the terms:
(-5 + 2x)(2x2 + 10x + 25) = 0

Reorder the terms:
(-5 + 2x)(25 + 10x + 2x2) = 0

Multiply (-5 + 2x) * (25 + 10x + 2x2)
(-5(25 + 10x + 2x2) + 2x * (25 + 10x + 2x2)) = 0
((25 * -5 + 10x * -5 + 2x2 * -5) + 2x * (25 + 10x + 2x2)) = 0
((-125 + -50x + -10x2) + 2x * (25 + 10x + 2x2)) = 0
(-125 + -50x + -10x2 + (25 * 2x + 10x * 2x + 2x2 * 2x)) = 0
(-125 + -50x + -10x2 + (50x + 20x2 + 4x3)) = 0

Reorder the terms:
(-125 + -50x + 50x + -10x2 + 20x2 + 4x3) = 0

Combine like terms: -50x + 50x = 0
(-125 + 0 + -10x2 + 20x2 + 4x3) = 0
(-125 + -10x2 + 20x2 + 4x3) = 0

Combine like terms: -10x2 + 20x2 = 10x2
(-125 + 10x2 + 4x3) = 0

Solving
-125 + 10x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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